Okay, so lets make another equation. We will add a variable P1 that is = 0 when there is another preference and =1 when there is not. So the equation becomes -
Y = P1X
P can represent any number of other preferences (other things to do) up to infinity. To keep things simple, let's say there is only one other. P = 0 when I want to stay up to watch David Letterman, and 1 when I do not.
To demonstrate that we can incorporate any number of preferences, we will add one more. P2 = 0 when my wife is coming home late (and I want to visit with her) and P2=1 when she is not. So the equation now would be Y = X (P1P2). Again, moving up to infinity. the vector of preferences that could exist other than going to bed can be represented as Pn, with n = to the total number of possible preferences, so our general equation would be Y = PnX.
So again, we have a free will choice that is the product of a deterministic process. So what am I missing, if anything.