I have "fine tuned" my example to satisfy the "nit pickers" here, even though the previous minor flaws did not affect the point of the "parable" in the least. What puzzles me is how otherwise intelligent (perhaps even brilliant) unbelievers here can not see the point of this example. Jesus was certainly right when He observed that few saw the point of his parables.
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WEASEL
Question: How many “good” words are there in English for the various numbers of letters, two, three, four, five and six etc. ? What then is the probability p that having one particular “good” word that a random letter change in that
same word will result in another "good" word ?
Source for number of 2, 3, 4, 5, 6, etc. letter
English words = WORDOX Dictionary:
http://aaron.doosh.net/lexicon/05LetterWords.html
p = (#good words -1) / (#possible words -1)
TWO LETTER WORDS
96 out of 26x26=576
p = 0.165
THREE LETTER WORDS
956 out of 26x26x26=17,576
p = 0.0543
FOUR LETTER WORDS
4155 out of 676x676=456,976
p= 0. 0091
FIVE LETTER WORDS
9936 out of 26x26x26x26x26=11,881,376
p= 0.00084
SIX LETTER WORDS
21,384 out of 17576x17576=308,915,776
p= 0.000069
SEVEN LETTER WORDS
In process
p= 0.00000??
Summarizing:
2 - p= 0.165
3 - p= 0.0543
4 - p= 0.0091
5 - p= 0.00084
6 - p= 0.000069
7 – p= 0.00000??